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That's called resolving the force into some other direction.
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Now, the key to all of this is to know that this angle,
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here, is the same as this angle here.
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In other words,
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if mg is acting down,
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that angle θ is the same as this angle θ here.
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This is going to be used all the time,
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so I'll tell you a little trick
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that tells you how I figured that out.
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θ Is the angle between the horizontal and the incline.
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Now, you've got to agree that
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if I draw perpendicular to the horizontal