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and you get the total kinetic energy.
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No problem there, right?
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Now what is the kinetic energy
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that you're summing up over each particle?
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It's 1/2 Mv^2. Has everybody seen that before?
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Okay, so that's the sum of classical kinetic energy
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over all the particles of interest in the problem,
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and the constant is just some number you put in
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to get the right units for your energy,
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depending on whether you use
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feet per second or meters per year or
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whatever,for the velocity.