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because what force are you going to use?
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It was something now, it is something later,
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it is positive now, it's negative later.
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So, we cannot apply this formula because F is not a constant.
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So, the usual trick in calculus is find me an interval in x,
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which is so narrow, and I'll make it as narrow as you insist,
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so that during that period I'll think that F is a constant
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and the constant value of F is just the function F at that time x,
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at that time where the location is x.
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So, for that tiny interval I can still say that F is constant;
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F over m is some constant over the tiny interval,
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then the change in kinetic energy will be then F of x times Δx.