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If you had two,
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each will generate its own potential when you do the integral.
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Then, we may then say E2 - E1;
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that's the same as (K2 + U2) - (K1 + U1)
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is equal to the work done by friction.
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Work done by friction is the shorthand for that integral
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which you can do only--
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you must divide the motion involved into pieces.
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For example,
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if you have a mass that swung to the left
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then turns around and goes back to the right,
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of course, again, it won't come back to the original A,