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2x cancels the 2, so I get f''(0)·x.
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But now, evaluate the derivative at x=0.
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That gets rid of this guy,
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and the derivative of my test function
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matches the derivative of the actual function,
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because this is the actual derivative of the actual function.
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Now, it follows that if you want to say,
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"How about the second derivative of this function?"
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Let's take the test function I have, or the approximation.
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Take a second derivative, and make sure that comes out right.
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I don't feel like writing this out, but try to do this in your head.
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Take two derivatives on the left-hand side