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It's just a number.
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Divide that by x2 and that by x2
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But I've got the sum of these two numbers in the bottom,
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and you can ask, "How do you do the division?"
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So, the trick, always, when you run into this problem,
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is to multiply the top and bottom by the complex conjugate of the bottom.
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Multiply it by x2-i·y2, top and bottom.
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Then, something nice happens to the denominator,
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because the denominator then becomes x2^2+y2^2,
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which is an ordinary real number, nothing complex about that.
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The numerator, you can open out the brackets.
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I don't know if I want to do that;