来自《耶鲁大学开放课程：基础物理 第1集 第1集》

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  This way when I take two derivatives, there will be no t left.
  这样的话 当我求二阶导数时 t就消失了
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  Well, unfortunately, we know this is not the right answer,
  遗憾的是 我们知道这还不是正确答案
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  because if you take the first derivative, I get 2t.
  因为如果对它求一阶导数 会得到2t
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  If I take the second derivative I get 2,
  如果我再求二阶导数就能得到2
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  but I want to get a and not 2.
  但我想要a不想得到2
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  Then it's very clear the way you patch it up
  很明显 弥补的方法就是
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  is you multiply it by this constant and now we're all set.
  乘以这个常数就全部搞定了
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  This function will have the right second derivative.
  这个函数会得出正确的二阶导数
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  So, this certainly describes a particle whose acceleration is a.
  它确实描述了一个加速度为a的质点的运动
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  The a is not dependent on time.
  a和时间无关
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  But the question is,
  但问题在于
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  is this the most general answer,
  这是不是通解