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in the limit in which they are approaching 0,
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the two will be, in fact, equal.
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If Δx is a finite amount, like 1 second,
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this will not be true because in the starting equation,
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Δx and Δt and Δ(v^(2)) were all assumed to be infinitesimal.
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So don't hesitate to do manipulations of this type,
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and I will do them quite often.
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So you've got to understand
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when it's okay and when it's not okay.
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What this means is, in a time Δt,
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this quantity changes by some amount,
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and in the same time, Δt,