来自《耶鲁大学开放课程：博弈论 第11集 第11集》

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  and suppose (?,?) is in fact Nash.
  假设(?,?)是纳什均衡
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  What I want to convince you of is that
  我想给大家证明的是
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  is going to be evolutionarily stable.
  是进化稳定策略
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  So I claim there's two possibilities, there are two cases.
  我说这里存在着两种可能性
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  The two cases are either it's the case that
  这两种可能性分别是
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  against ? does strictly better than ? against S' for all S'.
  对任意S’ ?对?严格优于?对S‘
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  So let's just be careful, since we know its Nash,
  这个要小心处理 知道它是纳什均衡
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  we already know that the payoff of ? against itself
  我们知道?对?的收益
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  is at least weakly better than any possible deviation,
  至少弱优于其他的可能变动
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  that's what it means to be Nash.
  这就是纳什均衡的含义
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  So everyone agree with that?
  大家都懂是吗
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  We know that ? is a best response to ?,
  既然?是?的最佳对策